shot_1_instruction = """
You will be given a question (problem specification) and will generate a correct Python program that matches the specification and passes all tests. You will NOT return anything except for the program.

Question: ```if-not:racket
Write a function called `repeat_str` which repeats the given string `src` exactly `count` times.
```
```if:racket
Write a function called `repeat-string` which repeats the given string `str` exactly `count` times.
```

You will use the following starter code to write the solution to the problem and enclose your code within delimiters.
```python
class Solution:
	def repeat_str(self, repeat, string):
```
""".strip()

shot_1_response = """
Okay, I need to write a Python function called repeat_str. The function should take two arguments: repeat and string. Wait, wait, wait. Wait the problem says, the function is called repeat_str and it should repeat the given string 'src' exactly 'count' times. But looking at the starter code, the parameters are named repeat and string. Oh right, so the function is defined as def repeat_str(self, repeat, string):.

So the task is to return the string repeated 'repeat' times. So for example, if the string is "a" and repeat is 3, it should return "aaa".

Hmm, how to approach this in Python. Well, strings in Python can be multiplied by an integer. So like "a" * 3 gives "aaa". So for the function, I can simply return string multiplied by repeat.

But wait, what if repeat is zero or negative? The problem says 'exactly count times', so I assume count is a non-negative integer. So perhaps the function should handle cases where repeat is zero by returning an empty string.

Wait, but looking at the starter code again: the function is in a class called Solution, so it's a method. So I need to make sure that the function correctly uses the parameters.

Wait, the parameters are repeat and string. So the function should return string repeated 'repeat' times. So the code would be something like:

return string * repeat

But wait, wait, what if repeat is zero? Then it will return an empty string, which is correct. What if repeat is negative? Well, the problem probably expects that the count is a non-negative integer, so perhaps we don't need to handle that case, assuming the test cases will provide valid inputs.

So the code is straightforward. So the function would look like this:

class Solution:
    def repeat_str(self, repeat, string):
        return string * repeat

Yes, that's it. Because string multiplied by an integer in Python gives the string repeated that many times. So this should handle all cases.
</think>
<answer>
```python
class Solution:
    def repeat_str(self, repeat, string):
        return string * repeat
```
</answer>
""".strip()

shot_2_instruction = """
You will be given a question (problem specification) and will generate a correct Python program that matches the specification and passes all tests. You will NOT return anything except for the program.

Question: Write function alternateCase which switch every letter in string from upper to lower and from lower to upper.
E.g: Hello World -> hELLO wORLD

You will use the following starter code to write the solution to the problem and enclose your code within delimiters.
```python
class Solution:
	
def alternateCase(self, s):
```
""".strip()

shot_2_response = """
Okay, I need to write a Python function called alternateCase that switches every letter in a string from upper to lower and vice versa. Hmm, so for example, 'Hello World' becomes 'hELLO wORLD'. Right, so each character's case is flipped.

Let me think about how to approach this. I remember that in Python, strings are iterable, so I can loop through each character. For each character, I check if it's uppercase and convert it to lowercase, or if it's lowercase and convert to uppercase.

Wait, but what about characters that are not letters, like numbers or symbols? They should remain unchanged, right. So I need to make sure that only letters are toggled.

So the plan is: iterate over each character in the string. For each character, check if it's a letter. If it is, toggle its case. Otherwise, leave it as is.

How do I check if a character is a letter? Oh right, using the isalpha() method. And to toggle the case, I can use the swapcase() method. Oh wait, wait, maybe that's a simpler approach. Because the swapcase() method does exactly that: it converts each uppercase letter to lowercase and each lowercase letter to uppercase, and leaves others unchanged.

So wait, does that mean I can just apply the swapcase() method to the string and return it? But wait, the starter code is a method inside a class, so the function is called on an instance of the Solution class. So, for example, in the method, I can simply return s.swapcase().

Wait, let me rethink about it and test this. For the example 'Hello World', applying swapcase() would give 'hELLO wORLD', which is exactly what's expected. So that's perfect.

So the function can be as simple as returning s.swapcase(). But wait, what about if the string is empty or has no letters? It should handle that fine, as swapcase() returns the same string.

So putting it all together, the code would be:

class Solution:
    def alternateCase(self, s):
        return s.swapcase()

Wait, but wait, is there any case where this might not work? Like, does swapcase() handle all Unicode letters correctly? I think in Python, it does, but the problem statement might not require handling those. But since the problem statement says to switch every letter, this solution should suffice.

So yes, that should work.
</think>
<answer>
```python
class Solution:
    def alternateCase(self, s):
        return s.swapcase()
```
</answer>
""".strip()

shot_3_instruction = """
You will be given a question (problem specification) and will generate a correct Python program that matches the specification and passes all tests. You will NOT return anything except for the program.

Question: Input

The input contains a single integer a (0 ≤ a ≤ 35).

Output

Output a single integer.

Examples

Input

3


Output

8


Input

10


Output

1024

Read the inputs from stdin solve the problem and write the answer to stdout (do not directly test on the sample inputs). Enclose your code within delimiters as follows. Ensure that when the python program runs, it reads the inputs, runs the algorithm and writes output to STDOUT.
```python
# YOUR CODE HERE
```
""".strip()

shot_3_response = """
Okay, I need to solve this problem where the input is a single integer a between 0 and 35, and I have to output another integer based on it. Let's look at the examples to figure out the pattern.

In the first example, the input is 3 and the output is 8. Hmm, 3 in binary is 11, and that's 3 in decimal. But wait, 8 is 2^3. Oh right, 3+1 is 4, 2^4 is 16? No, wait, that doesn't fit. Wait, 2^3 is 8, which is the output. So maybe the output is 2^a.

Wait, let's check the second example. Input is 10, output is 1024. 2^10 is 1024, which matches. So yeah, that's the pattern. So the problem is to compute 2 raised to the power of a.

But wait, let me think again. The first example: a=3, 2^3=8. Second example: a=10, 2^10=1024. So yes, that's the rule.

So the task is to read an integer a, compute 2^a, and print it.

But wait, wait. Let me check the constraints. The input a can be 0. So what's 2^0? It's 1. So if a is 0, output is 1.

But how to handle this in Python. It's straightforward: read a, compute 2**a, print it.

So the steps are:

1. Read the input as an integer. Since the input is from stdin, I can use input().strip() and convert to int.

2. Compute 2 ** a.

3. Print the result.

Now, let's write the code.

Wait, but in Python, when a is 0, 2**0 is 1, which is correct.

So the code would be:

a = int(input())
print(2 ** a)

Yes, that's simple. So I'll write that.
</think>
<answer>
```python
a = int(input())
print(2 ** a)
```
</answer>
""".strip()

